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Two blocks with masses M and m are in contact with each other and are resting on a horizontal frictionless floor. When horizontal force is applied to the heavier, the blocks accelerate to the right. The force between the two blocks is

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A(M + m) F/m

BMF/m

CmF/M

DmF/(M + m)

Answer:

D. mF/(M + m)

Read Explanation:

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from the free body diagram

FN=MaF-N=Ma ..................(1)

N=maN=ma ...........................(2)

Therefore, a=Fm+Ma=\frac F{m+M} ............ from eqn (2)

we get N=mF(m+M)N=\frac {mF}{(m+M)}


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