App Logo

No.1 PSC Learning App

1M+ Downloads

What is the degree of p(x)+q(x):

p(x)=4x4+3x2+6x+9p(x)=4x^4+3x^2+6x+9,q(x)=5x4+6x3+8q(x)=5x^4+6x^3+8

A8

B3

C4

D6

Answer:

C. 4

Read Explanation:

p(x)=4x4+3x2+6x+9p(x)=4x^4+3x^2+6x+9,q(x)=5x4+6x3+8q(x)=5x^4+6x^3+8

p(x)+q(x)=9x4+6x3+3x2+6x+17p(x)+q(x)=9x^4+6x^3+3x^2+6x+17

degree of p(x)+q(x) =4


Related Questions:

Simplify: 3x(x - 6) + x² + 6x - 9 + 24 - x³
Find the polynomial satisfying the given set of conditions: The first degree polynomial with P(1)=1 and P(3)=2
image.png
The number of solutions to the pair of linear equations 5x-3y = 7 and 7x + 4y = 18 is:

If the zeros of the quadratic polynomialax2+bx+cax^2+bx+c,c 0 are equal , then :