$$Which of the following is not completely divisible in: $16^{200}-2^{400}$ A3B2C20D16Answer: D. 16 Read Explanation: 16200−240016^{200}-2^{400}16200−2400=4400−4200=4^{400}-4^{200}=4400−4200n=400;even,16+4and16−4arecompletelydivisibleinit.</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true"> {n = 400 ; even}, 16+4 and 16-4 are completely divisible in it.</p><p style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px" data-pxy="true">n=400;even,16+4and16−4arecompletelydivisibleinit.</p><pstyle="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px"data−pxy="true">20,12 are completely divisible in it. Read more in App