Sum of 'n' terms of the series √3 + √12 + √27 +√48 + ... is given by :
An (n + 1) / 2
B√3 / 2 n (n + 1)
Cn(n + 1) / √3
Dn(n+1)/3
An (n + 1) / 2
B√3 / 2 n (n + 1)
Cn(n + 1) / √3
Dn(n+1)/3
Related Questions:
Which of the following interchanges of numbers would make the given equation correct?
$6 \times 40 \div 8 + 2 - 5 = 11$