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Sum of 'n' terms of the series √3 + √12 + √27 +√48 + ... is given by :

An (n + 1) / 2

B√3 / 2 n (n + 1)

Cn(n + 1) / √3

Dn(n+1)/3

Answer:

B. √3 / 2 n (n + 1)


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