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The area of a sector of a circle is 66 cm² and the angle of the sector is 60°. Find the radius of the circle.

A5215\sqrt{21}

B3143\sqrt{14}

C373\sqrt{7}

D6146\sqrt{14}

Answer:

3143\sqrt{14}

Read Explanation:

The area of a sector of a circle is 66 cm² and the angle of the sector is 60°

Concept used:

Area of a sector = πr² × θ/360°

θ = angle of the sector

r = radius

Calculation:

According to the question,

60/360×πr2=6660/360\times{\pi{r^2}}=66

πr2=66×6\pi{r^2}=66\times6

22/7×r2=66×622/7\times{r^2}=66\times6

r2=66×6×722r^2=\frac{66\times6\times7}{22}

r2=126r^2=126

r=314r=3\sqrt{14}


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