Solution:
Given:
Let 'a' be the side of square, l be the length and b be the breadth of the rectangle
The area of a square and a rectangle are equal ⇒ a2 = l × b
The length of the rectangle is greater than the side of square by 9 cm and its breadth is less than the side of square by 6 cm
⇒ l = a + 9
⇒ b = a – 6
Formula used:
Area of Square = side2
Area of Rectangle = length × breadth
Perimeter of Rectangle = 2 × (length + breadth)
Calculation:
According to the question,
Area of Square = Area of Rectangle
⇒ a2 = l × b
⇒ a2 = (a + 9) × (a – 6)
⇒ a2 = a2 – 6a + 9a – 54
⇒ 3a = 54
⇒ a = 18
⇒ l = 18 + 9 = 27 and b = 18 – 6 = 12
Perimeter of the Rectangle = 2 × (length + breadth)
Perimeter of the Rectangle = 2 × (27 + 12) = 78 cm
∴ The correct answer is 78 cm.