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The base edges and lateral edges of a square pyramid are equal. If the base edge is 6 cm then the volume of the pyramid is :

A108 cu.cm

B108√2 cu.cm

C36 cu.cm

D36√2 cu.cm

Answer:

D. 36√2 cu.cm

Read Explanation:

V=a326=6326=362V = \frac{a^3\sqrt2}{6}=\frac{6^3\sqrt2}{6}=36\sqrt2

V=13Ah=13a2hV=\frac{1}{3}Ah=\frac{1}{3}a^2h

h=a2(a22)2h=\sqrt{a^2-(\frac{a\sqrt2}{2})^2}

=a2a22=\sqrt{a^2-\frac{a^2}{2}}

h=a2h=\frac{a}{\sqrt2}

v=13a2a2=a332v=\frac{1}{3}a^2\frac{a}{\sqrt2}=\frac{a^3}{3\sqrt2}


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