Question

The centre of the 'Mohr's circle' for a two-dimensional stress system lies

• A. On X-axis
• B. On Y-axis
• C. On Z-axis
• D. On 45° of X-axis

Answer 1

Answer:

A. On X-axis

The centre of Mohr's circle for a two-dimensional stress system lies on the X-axis. This is because the Y-coordinate is zero in the centre equation, which is given as $(\frac{\sigma_x+\sigma_y}{2}, 0), $Where$ \sigma_x$ and $\sigma_y$ are the normal stress. The radius equation includes normal stress on a given plane in x and y-direction and shear stress on the x-y plane. The radius of Mohr Circle for a given state of stress, $R=\frac12\sqrt{(\sigma_{x} - \sigma_{y}) ^ 2 +4 \tau_{xy} ^ 2}$ where $\tau_{xy}$ = shear stress on the x-y plane.