Solution:
Given:
Principal amount = x
Interest for 2nd year = Rs. 770
Interest for 3rd year = Rs. 847
Concept used:
For 1st year interest = (P × R × T)/100
For 2nd year interest,
⇒ ((P + 1st year interest) × R × T) /100
Calculation:
Let, Rate of interest = R
Difference between the CI of two successive years = 847 - 770 = Rs. 77
So, 77 is the one-year interest on Rs. 770.
⇒ (770 × R × 1)/100 = 77
⇒ 770 × R = 77 × 100
⇒ R = 7700/770 = 10
Interest on x for 1st year = (x × 10 × 1)/100 = x/10 = 0.1x
Principal amount for 2nd year = (x + 0.1x) = 1.1x
Interest on 1.1x for 2nd year = (1.1x × 10 × 1)/100 = 0.11x
Now, 0.11x = Rs. 770
⇒ x = 770/0.11 = 770 × 100/11 = Rs. 7000
∴ The sum of the money is Rs. 7000.