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The compound interest on ₹40,000 at 6% per annum is ₹4,944. What is the period (in years) for which the amount is invested?

A5 years

B4 years

C3 years

D2 years

Answer:

D. 2 years

Read Explanation:

Solution:

Given :

Principle = Rs 40000 

Rate of interest = 6% 

Total interest = Rs 4944 

Formula used :

Amount=P[(1+r100)n]Amount=P[(1 + \frac{r}{100})^n] 

(where P = principle, r = rate of interest and n = number of years)

Calculations :

Total amount = Principle + interest = 40000 + 4944

⇒ 44944 

Now according to the question

40000[(1+6100)n]40000[(1+\frac{6}{100})^n]  = 44944

(106100)n=4494440000(\frac{106}{100})^n=\frac{44944}{40000}

(5350)n=28092500(\frac{53}{50})^n=\frac{2809}{2500}

n = 2 

∴ Period of time is 2 years


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