Question

The diagonal of the square is 8√2 cm. Find the diagonal of another square whose area is triple that of the first square.

• A. $$8\sqrt 5$$
• B. $$8\sqrt 3$$
• C. $$8\sqrt 2$$
• D. $$8\sqrt 6$$

Answer 1

Answer:

$$8\sqrt 6$$

Solution: Concept Used: Diagonal of square = √2 a Calculations: Diagonal of square = √2 a So, √2 a = 8√2 ⇒ a = 8 ⇒ a² = 64 cm² So, the area if another square = 3(64) = 192 So, it's diagonal= √2 a = √2 × √192 = 8√6 cm Hence, The Required value is 8√6 cm