Question

The digit in unit’s place of the product 81 × 82 × 83 × ... × 89 is:

• A. 1
• B. 0
• C. 3
• D. 9

Answer 1

Answer:

B. 0

The digit in unit’s place = unit’s digit in the product 1 × 2 × 3 × .... × 9 = 0 The digit in unit’s place = unit’s digit in the product 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 See the 5 and 8 from given unit place of product will multiply and give 0 at unit place and then other unit place number will multiply with 0 and final number will be 0 at unit place.