Question

The dimensions of acceleration due to gravity are .....

• A. $[M^0L^1T^(-2)]$
• B. $[M^1 L^(-1)T^(-2)]$
• C. $[M^(-1) L^2 T^(-1)]$
• D. $[M^0L^(-1)T^2]$

Answer 1

Answer:

$[M^0L^1T^(-2)]$

The unit of acceleration is $m/s^2$.

$m/s^2 = [L^1 T^(-2)] = [M^0 L^1 T^(-2)]$.