Question

The distance between two points (-6,y) and (18,6) is 26 units. Find the value of y.

• A. 4
• B. -4
• C. 6
• D. -6

Answer 1

Answer:

B. -4

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$D=\sqrt{(18-(-6))^2+(6-y)^2}$

$26=\sqrt{(24)^2+(6-y)^2}$

squaring on both sides

$676 = 24^2 +(6-y)^2$

$676-576=(6-y)^2$

$100=(6-y)^2$

$10^2=(6-y)^2$

$10=6-y$

$y=-4$