App Logo

No.1 PSC Learning App

1M+ Downloads
The equation x²-6x+9=0 can be written as:

A(x+3)2=0(x + 3)^2 = 0

B(x3)2=0(x-3)^2 = 0

C(x2)(x3)2=0(x-2)(x-3)^2 = 0

D(x2)(x3)=0(x-2)(x-3) = 0

Answer:

(x3)2=0(x-3)^2 = 0

Read Explanation:

(x3)2=0(x-3)^2 = 0


Related Questions:

The roots of the equation ax2+bx+c=0ax^2+ bx + c = 0 are equal if:

The dimensions of a cuboid are in the ratio 1:2:3 and its total surface area is 88m². Find the dimensions?
image.png

p(x)=2x2+3x+7p(x) =2x^2+3x+7,q(x)=6x2+8x9q(x)=6x^2+8x-9Find q(x)-p(x)

Simplify 3(3x2)+x(4x2)+1512.3(3x - 2) + x(\frac{4x}{2})+15-12.