The equation x²-6x+9=0 can be written as:

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A $(x + 3)^2 = 0$

B $(x-3)^2 = 0$

C $(x-2)(x-3)^2 = 0$

D $(x-2)(x-3) = 0$

Answer:

(x-3)^2 = 0

$(x-3)^2 = 0$

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