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The equation x2+kx+9=0x^2 + kx + 9 = 0 has two equal roots, then the value of k is

A±6

B±3

C±0

D±9

Answer:

A. ±6

Read Explanation:

For a quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0 to have two equal roots, its discriminant (DD) must be equal to zero:
D=b24ac=0D = b^2 - 4ac = 0


Step 1: Identify the coefficients
From the given equation x2+kx+9=0x^2 + kx + 9 = 0:

  • a=1a = 1

  • b=kb = k

  • c=9c = 9

Step 2: Substitute values into the discriminant formula
k24(1)(9)=0k^2 - 4(1)(9) = 0
k236=0k^2 - 36 = 0

Step 3: Solve for kk
k2=36k^2 = 36
k=±36k = \pm\sqrt{36}
k=±6k = \pm 6


Final Answer

The value of kk is ±6\pm 6 (either +6+6 or 6-6).


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