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The height of a right circular cylinder is three times its radius. If the curved surface area of the right circular cylinder is 3696 cm², then the volume of the cylinder is equal to (taking ∏ = 22/7):

A25,992 cm³

B25,972 cm³

C25,892 cm³

D25,872 cm³

Answer:

D. 25,872 cm³

Read Explanation:

For a cylinder:

  • CurvedSurfaceArea(CSA)=(2πrh)Curved Surface Area (CSA) = (2\pi r h)

  • Volume=(πr2h)Volume = (\pi r^2 h)

Given: (h = 3r), CSA = 3696 cm²,(π=227)(\pi = \frac{22}{7})

Use CSA

  • 2πrh=36962\pi r h = 3696

Substitute (h = 3r):
2πr(3r)=36962\pi r (3r) = 3696
6πr2=36966\pi r^2 = 3696
6×227×r2=36966 \times \frac{22}{7} \times r^2 = 3696
1327r2=3696\frac{132}{7} r^2 = 3696
r2=3696×7132=196r^2 = \frac{3696 \times 7}{132} = 196

r=14 cmr = 14 \text{ cm}

Find volume

V=πr2h=πr2(3r)=3πr3V = \pi r^2 h = \pi r^2 (3r) = 3\pi r^3
=3×227×143= 3 \times \frac{22}{7} \times 14^3
=3×227×2744= 3 \times \frac{22}{7} \times 2744
=3×22×392=25872= 3 \times 22 \times 392 = 25872

Final Answer: 25872 cm³


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