The LCM and HCF of two numbers are 20 and 120 respectively. if one number is 50% more than the other number. What is the smaller number of the twoA20B40C60D80Answer: B. 40 Read Explanation: let the numbers be N1, N2 LCM = 120, HCF = 20 If N1 = 100, N2 - 150 N1/N2 = 100/150 = 2/3 = a/b N1 = HCF × a = 20 × 2 = 40 N2 = HCF × b = 20 × 3 = 60Read more in App