Question

The least number which when divided by 4, 5, 6 and 7 leaves 3 as remainder, but when divided by 9 leaves no remainder is:

• A. 848
• B. 432
• C. 864
• D. 423

Answer 1

Answer:

D. 423

LCM of 4, 5, 6, 7 4 = 2 × 2 × 1 5 = 5 × 1 6 = 2 × 3 × 1 7 = 7 × 1 LCM = 2 × 2 × 3 × 5 × 7 = 420 we have to add 3 to LCM = (420 + 3) = 423