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The lengths of two adjacent sides of a parallelogram are 5 cm and 3.5 cm respectively. One of its diagonals is 6.5 cm long, the area of the parallelogram is

A8√3 sq.cm

B12√3 sq.cm

C15 sq. cm

D10√3sq.cm

Answer:

D. 10√3sq.cm

Read Explanation:

Let consider ABCD is a parallelogram.

Given,

AB = 5 and BC = 3.5 and AC = 6.5

Area of ∆ABC:

s = (5+3.5+6.5)2=7.5\frac{(5 + 3.5 + 6.5)}{2}=7.5

Area =(7.5×(7.55)×(7.53.5)×(7.56.5)\sqrt{(7.5\times{(7.5-5)}\times{(7.5-3.5)}\times{(7.5-6.5)}}

=(7.5×2.5×4×1=\sqrt{(7.5\times{2.5}\times{4}\times{1}}

=53=5\sqrt{3}

Area of parallelogram =2×53=103=2\times{5\sqrt{3}}=10\sqrt{3} sq. cm


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