The moment of inertia of a triangular section with base 'b. and height .1.1. about an axis through the centre of gravity and parallel to the base is given as
A(bh^3)/12
B(bh^3)/24
C(bh^3)/36
D(bh^3)/48
No.1 PSC Learning App
★
★
★
★
★
A(bh^3)/12
B(bh^3)/24
C(bh^3)/36
D(bh^3)/48