Question

The perimeter of two squares are 40 cm and 32 cm. The perimeter of a third square whose area is the difference of the area of the two squares is

• A. 24 cm
• B. 42 cm
• C. 40 cm
• D. 20 cm

Answer 1

Answer:

A. 24 cm

Side of one square $=\frac{40}{4}=10cm$

Perimeter $=4\times{(side)}=32$

Side of other square $=\frac{32}{4}=8cm$

According to the question,

Area of third square

$= (10)^2-(8)^2 = 100-64 = 36 sqcm$

Side of third square $=\sqrt{36}=6cm$

Its perimeter = 4 × 6 = 24 cm.