The product of the roots of 3x²

Challenger App

★

1M+ Downloads

The product of the roots of 3x² - 13x + 6 = 0 is:

Answer:

$ax^2+bx+c=0$

product root = $\frac{c}{a}$

sum root = $-\frac{b}{a}$

so product root $=\frac{6}{3}=2$

Related Questions:

Find the reminder when $p(x)=2x^4+4x^2-1$ is divided by $x+1$

What is the degree of p(x)+q(x):

$p(x)=4x^4+3x^2+6x+9$ , $q(x)=5x^4+6x^3+8$

If $x^5+2x^4+x+6$ is divided by g(x), and quotient is $x^2+5x+7$ , then the positive degree of g(x) is :