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The radius of circle is so increased that its circumference increased by 10%.The area of the circle then increases by?

A21

B20

C10.5

D10

Answer:

A. 21

Read Explanation:

Solution:

Increased circumference of the circle is 10%.

Intial Circumference =2πr1=100= 2\pi{r_1}=100 --------------(1)

New Circumference after increase in area =2πr2=110=2\pi{r_2}=110 --------------(2)

By (1)÷(2)(1) \div{(2)}

2πr12πr2=100110\frac{2\pi{r_1}}{2\pi{r_2}}=\frac{100}{110}

r1r2=1011\frac{r_1}{r_2}=\frac{10}{11}

Area A1=πr12A_1=\pi{r^2_1}

A2=πr22A_2=\pi{r^2_2}

A1=100πA_1=100\pi

A2=121πA_2=121\pi

Change in area =121π100π=121\pi-100\pi

=21π=21\pi

% increase in area =21100×100=\frac{21}{100}\times{100}=21%


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