Solution:
Increased circumference of the circle is 10%.
Intial Circumference =2πr1=100 --------------(1)
New Circumference after increase in area =2πr2=110 --------------(2)
By (1)÷(2)
2πr22πr1=110100
r2r1=1110
Area A1=πr12
A2=πr22
A1=100π
A2=121π
Change in area =121π−100π
=21π
% increase in area =10021×100=21%