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The ratio of the length and the width of a rectangle is 4 ∶ 3, and its perimeter is the same as the perimeter of a right-angled triangle whose sides containing the right angle are 7 cm and 24 cm long, What is the area of the rectangle?

A192 sq.cm

B176 sq.cm

C204 sq.cm

D180 sq.cm

Answer:

A. 192 sq.cm

Read Explanation:

Solution:

Given:

length : breadth = 4 : 3

right angled triangle sides = 7 cm and 24 cm

Formula used:

Perimeter of right angled triangle =a+b+a2+b2=a+b+\sqrt{a^2+b^2}

Perimeter of rectangle = 2 × (length + breadth)

Area of rectangle = length × breadth

Calculations:

Let the length and width of rectangle be 4x and 3x

Required perimeter of right angled triangle =7+24+72+242=7+24+\sqrt{7^2+24^2}

=31+49+576=31+\sqrt{49+576}

=31+625=31+\sqrt{625}

=31+25=31+25

= 56 cm (which is equal to the perimeter of rectangle)

Now, 56 = 2 × (4x + 3x)

=> 56 = 2 × 7x

=> x = 4

Required length(4x) = (4 × 4) = 16 cm and width(3x) = ( 3 × 4) = 12 cm

So, required area of rectangle = (16 × 12) = 192 sq.cm.

The answer is 192 sq.cm.


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