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The ratio of the moments of resistance of a solid circular shaft of diameter D and a hollow shaft (external diameter D and internal diameter d) is

AD⁴/(D⁴-d⁴)

BD³ /(D³ -d³ )

C(D⁴-d⁴)/D⁴

D(D³ -d³ )/D³

Answer:

A. D⁴/(D⁴-d⁴)


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