Question

The ratio of the moments of resistance of a solid circular shaft of diameter D and a hollow shaft (external diameter D and internal diameter d) is

• A. D⁴/(D⁴-d⁴)
• B. D³ /(D³ -d³ )
• C. (D⁴-d⁴)/D⁴
• D. (D³ -d³ )/D³

Answer 1

Answer:

A. D⁴/(D⁴-d⁴)