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The reaction at the two supports of a simply supported beam carrying a uniformly distributed load over its entire span is: (the intensity of loading on the beam is w/unit length and I is the length of the beam).

Awl, wl/2

Bwl/ 2, wl/2

Cw/2, w/2

Dwl/4, wl/4

Answer:

B. wl/ 2, wl/2

Read Explanation:

For a simply supported beam with uniformly distributed load over the entire span, the reaction at each support is half of the total load, i.e., wl/2. Using the equilibrium condition in y- direction and moment equation, we getRA=RB=wl/2 R_{A} = R_{B} = wl / 2

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