Challenger App

No.1 PSC Learning App

1M+ Downloads
The resistance of a wire is R the wire is stretched to doubled its length resistance of the wire becomes:

AR/2

B4R

C2R

DR/4

Answer:

B. 4R

Read Explanation:

  • The electrical resistance (R) of a wire is determined by its material resistivity (ρ), length (L), and cross-sectional area (A).

  • The formula for resistance is R = ρ * (L / A).

  • Resistivity (ρ) is an intrinsic property of the material itself.

Effect of Stretching a Wire

  • When a wire is stretched, its volume remains constant (assuming no material is lost).

  • If the length of the wire is increased, its cross-sectional area must decrease proportionally to maintain constant volume.

  • Let the original length be L1 and the original cross-sectional area be A1. The original resistance R1 = ρ * (L1 / A1).

  • If the wire is stretched to double its length, the new length L2 = 2 * L1.

  • Since the volume (V = L * A) is constant, V1 = V2, which means L1 * A1 = L2 * A2.

  • Substituting L2 = 2 * L1, we get L1 * A1 = (2 * L1) * A2.

  • This implies that the new cross-sectional area A2 = A1 / 2.

  • The new resistance R2 = ρ * (L2 / A2).

  • Substituting the new length and area: R2 = ρ * ((2 * L1) / (A1 / 2)).

  • Simplifying this expression: R2 = ρ * (4 * L1 / A1).

  • Since the original resistance R1 = ρ * (L1 / A1), we can substitute R1 into the equation for R2.

  • Therefore, R2 = 4 * (ρ * L1 / A1) = 4 *R1.

  • If the original resistance of the wire is R, and its length is doubled by stretching, the new resistance becomes 4R.


Related Questions:

The filament of a bulb is made extremely thin and long in order to achieve?
If the resistance of a conductor is doubled while keeping the potential difference across its ends constant, what will happen to the current flowing through it?

താഴെപ്പറയുന്നവയിൽ വൈദ്യുതി മൂലമുള്ള തീപിടിത്തത്തിന്റെ കാരണമാകാവുന്നത് ഏതെല്ലാം?
i. ഇലക്ട്രിക് ആർക്
ii. ഇൻസുലേഷൻ തകരാർ
iii. സർക്യൂട്ട് ബ്രേക്കറിൻ്റെ ഉപയോഗം
iv. ശരിയല്ലാത്ത എർത്തിംഗ്

Transformer works on the principle of
An electric heater rated 1000 W and an electric geyser rated 2000 W are med for 4 hours daily. The energy consumed in 10 days (in kWh) is?