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The shear force obtained at the midpoint of the cantilever beam is 12 kN. What is the value of uniformly distributed load w (kN/m) acting over the entire length, if the span length of the beam is 4 m?

A2

B4

C6

D8

Answer:

C. 6

Read Explanation:

Given: SFxx=12kNSF_ {x - x} =12 kN, x = 2m (mid-point) Calculation: FXX=wx12=w×2w=6kN/m.F_{X - X} =wx \Rightarrow 12=w\times 2 \Rightarrow w=6 kN/m.

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