The smallest 1-digit number to be added to the 6-digit number 405437 so that it is completely divisible by 11 is:A1B2C4D3Answer: A. 1 Read Explanation: divisibility of 11 is the sum of alternative position should be equal 405437405437 4054374+5+3=0+4+74+5+3=0+4+7 4+5+3=0+4+712≠1112\ne1112=11 $smallest number is 1 Read more in App