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The smallest 1-digit number to be added to the 6-digit number 405437 so that it is completely divisible by 11 is:

A1

B2

C4

D3

Answer:

A. 1

Read Explanation:

divisibility of 11 is the sum of alternative position should be equal

405437405437

4+5+3=0+4+74+5+3=0+4+7

121112\ne11 $

smallest number is 1


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