Question

The smallest natural number which is divisible by 26, 8, 11 and 13 is:

• A. 1201
• B. 1082
• C. 1126
• D. 1144

Answer 1

Answer:

D. 1144

Find the LCM of 26, 8, 11, and 13.

Prime factorization

• (26 = 2 \times 13)

• (8 = 2^3)

• (11 = 11)

• (13 = 13)

Take highest powers of all primes

$\text{LCM} = 2^3 \times 11 \times 13$
$= 8 \times 143 = 1144$