The sum of ages of 5 children born at intervals of four years is 80. What is the age of the eldest child?A16B24C18D28Answer: B. 24 Read Explanation: 1. Define the variables:Let the age of the youngest child be x years.Since the children are born at intervals of four years, the ages of the other children will be x + 4, x + 8, x + 12, and x + 16.2. Set up the equation:The sum of their ages is 80: x + (x + 4) + (x + 8) + (x + 12) + (x + 16) = 803. Solve the equation:5x + 40 = 805x = 80 - 405x = 40x = 40 / 5x = 84. Calculate the age of the eldest child:Age of the eldest child = x + 16 = 8 + 16 = 24 yearsTherefore, the age of the eldest child is 24 years. Read more in App