Question

The sum of four times a number and 3 times of another number is 43. The difference of two times the second number from three times of the first number is 11. Find the numbers.

• A. 7 , 5
• B. 2, 3
• C. 1 , 5
• D. 6 , 5

Answer 1

Answer:

A. 7 , 5

numbers x and y 4x+3y = 43 ---(1) 3x-2y=11 ---(2) 3 x (1) => 12x9y=129 ---(3) 4 x (2) => 12x-8y=44 ---(4) (3) - (4) => 17y = 85 y=85/17 = 5 3x-2y = 11 3x-10 = 11 3x=21 x=7