Question

The sum of the three numbers in a GP is 26 their product is 216 . Find the numbers :

• A. 3, 9, 27
• B. 2,6,18
• C. 4, 8, 16
• D. 5, 10, 20

Answer 1

Answer:

B. 2,6,18

Let the numbers be a/r, a, ar a/r + a + ar = 26 a/r × a × ar = 216 a³ = 216 a = 6 a/r + a + ar = 26 a(1/r + 1 + r) = 26 a(1 + r +r²)/r=26 6 + 6r + 6r² = 26r 6r² - 20r + 6 = 0 On solving r = 3 or r = 1/3 a/r = 6/3 = 2 a = 6 ar = 18