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The third proportional to (x2y2)(x^2 - y^2) and (x - y) is:

A(x - y)

B(xy)(x+y)\frac{(x-y)}{(x+y)}

C(x+y)(xy)\frac{(x+y)}{(x-y)}

D(x + y)

Answer:

(xy)(x+y)\frac{(x-y)}{(x+y)}

Read Explanation:

Given:

First number (a) =x2y2=x^2-y^2

Second number (b) = (x - y)

Formula used:

Third proportional =(2ndnumber(a))2firstnumber(b)=\frac{(2nd number(a))^2}{first number(b)}

(x2y2)=(xy)×(x+y)(x^2-y^2)=(x-y)\times{(x+y)}

Calculation:

Third proportional =(xy)2×(x2y2)=(x-y)^2\times{(x^2-y^2)}

(xy)×(xy)(xy)×(x+y)⇒\frac{(x-y)\times(x-y)}{(x-y)\times(x+y)}

(xy)(x+y)⇒\frac{(x-y)}{(x+y)}

∴ The correct answer is (xy)(x+y)\frac{(x-y)}{(x+y)}


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