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The total surface area of right circular cone is 360∏ m², the height of the right circular cone (in m) ; r=10m

A15m

B18m

C24m

D20m

Answer:

C. 24m

Read Explanation:

Let 'l' be the slant height of the right circular cone.

According to the question

A=πrl+πr2A=\pi rl+\pi r^2

360π=[(π×10×l)+(π×102)]360\pi=[(\pi \times 10 \times l)+(\pi \times 10^2)]

360=10l+100360=10l+100

36=l+1036=l+10

l=26ml=26m

now,

l2=r2+h2l^2=r^2+h^2

262=102+h226^2=10^2+h^2

h2=676100h^2=676-100

h=24h=24


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