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The two sides holding the right-angle in a right-angled triangle are 3 cm and 4 cm long. The area of its circumcircle will be:

A5πcm^2$$

B7πcm^2$$

C6.75π6.75π cm^2$$

D6.25π6.25π cm^2$$

Answer:

6.25π6.25π cm^2$$

Read Explanation:

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The two sides holding the right angle in a right-angled triangle are 3 cm and 4 cm long,

⇒ Length of hypotenuse = (32 + 42)1/2 = 5 cm

⇒ Radius of circum-circle =52=2.5cm=\frac{5}{2}=2.5 cm

∴ Area =227×(2.5)2=\frac{22}{7}\times{(2.5)^2}= 6.25π cm2


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