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The value of 0.16ˉ+0.15ˉ0.13ˉ0.1\bar{6}+0.1\bar{5}-0.1\bar{3} is:

A1790\frac{17}{90}

B3435\frac{34}{35}

C2363\frac{23}{63}

D1999\frac{19}{99}

Answer:

1790\frac{17}{90}

Read Explanation:

0.16ˉ+0.15ˉ0.13ˉ0.1\bar{6}+0.1\bar{5}-0.1\bar{3}

0.16ˉ=0.16666...0.1\bar{6}=0.16666...

x=0.16666.....x=0.16666.....

10x=1.66666...10x=1.66666...

10xx=1.510x-x=1.5

9x=1.59x =1.5

x=1.59x=\frac{1.5}{9}

Similarly,

0.15ˉ=1.490.1\bar{5}=\frac{1.4}{9}

0.13ˉ=1.290.1\bar{3}=\frac{1.2}{9}

0.16ˉ+0.15ˉ0.13ˉ=1.59+1.491.290.1\bar{6}+0.1\bar{5}-0.1\bar{3}=\frac{1.5}{9}+\frac{1.4}{9}-\frac{1.2}{9}

=1.5+1.41.29=1.79=\frac{1.5+1.4-1.2}{9}=\frac{1.7}{9}

=1790=\frac{17}{90}


Related Questions:

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