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The value of

{4−3×[7−8×(2×4−10)]}=\{4 - 3 \times [7 - 8 \times (2 \times 4 - 10)]\} =

A65

B73

C-65

D-25

Answer:

C. -65

Read Explanation:

The value of the expression is −65-65.

Following the BODMAS rule (Brackets, Orders, Division, Multiplication, Addition, Subtraction), we solve from the innermost brackets outward:

  1. Solve the Parentheses ( ):

    • Inside the parentheses, perform multiplication first:
      2×4=82 \times 4 = 8

    • Then subtract:
      8−10=−28 - 10 = -2

  2. Solve the Square Brackets [ ]:

    • Substitute −2-2 back into the bracket:
      7−8×(−2)7 - 8 \times (-2)

    • Multiply first:
      −8×(−2)=+16-8 \times (-2) = +16

    • Then add:
      7+16=237 + 16 = 23

  3. Solve the Curly Braces { }:

    • Substitute 2323 back into the braces:
      4−3×234 - 3 \times 23

    • Multiply first:
      3×23=693 \times 23 = 69

    • Finally, subtract:
      4−69=−654 - 69 = -65


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