The value of (a+b1)r(a−b1)s÷(b+a1)r(b−a1)s is:
A$(\frac{a}{b})^{r+s}$
B$(\frac{b}{a})^{r+s}$
C$({a}{b})^{r+s}$
D$(\frac{a^r}{b^s})$
Answer:
$(\frac{a}{b})^{r+s}$
Read Explanation:
The simplified value of the given expression is (ba)r+s.
The given expression is:
(b+a1)r(b−a1)s(a+b1)r(a−b1)s
Simplify the fractional terms inside each bracket:
(a+b1)=bab+1
(a−b1)=bab−1
(b+a1)=aab+1
(b−a1)=aab−1
Substitute these back into the expression:
(aab+1)r⋅(aab−1)s(bab+1)r⋅(bab−1)sSeparate the numerators and denominators using exponent rules:
ar(ab+1)r⋅as(ab−1)sbr(ab+1)r⋅bs(ab−1)sCancel out the common terms (ab+1)r and (ab−1)s from the top and bottom:
ar⋅as1br⋅bs1=br⋅bsar⋅asCombine using the law of indices (xm⋅xn=xm+n):
br+sar+s=(ba)r+s
