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The weight of Ayush and Abhishek are in the ratio of 8 ∶ 5. Abhishek's weight increases by 40 percent and the total weight of Ayush and Abhishek both increase by 60 percent. If the total weight becomes 104 kg, then what is the weight of Ayush after the increment?

A60 kg

B75 kg

C69 kg

D72 kg

Answer:

C. 69 kg

Read Explanation:

Given:

The weight of Ayush and Abhishek is in the ratio of 8:5.

Abhishek's weight increased by 40%.

The total weight of Ayush and Abhishek both increased by 60%.

The total weight becomes 104 kg.

Formulas:

Increase in weight = Originalweight×Percentageincrease100Original weight\times\frac{Percentage increase}{100}

Solution:

Let's assume:

The weight of Ayush = 8x

The weight of Abhishek = 5x

Abhishek's weight after the increase:

Increase in weight = 5×401005\times\frac{40}{100}

Increase in weight = 2x

New weight of Abhishek = 5x + 2x = 7x

Total weight of Ayush and Abhishek after the increase:

Increase in weight = (8x +5x)×60100\times\frac{60}{100}

Increase in weight = 13x×60100\times\frac{60}{100}

Increase in weight = 7.8x

Total weight after the increase:

Total weight = 8x + 5x + 7.8x

Total weight = 20.8x

Given that the total weight becomes 104 kg, we can set up the equation:

20.8x = 104

To solve for x, we divide both sides of the equation by 20.8:

x = 10420.8\frac{104}{20.8}

x = 5

Now that we know x, we can find the weight of Abhishek after the increment:

Weight of Abhishek = 7x

Weight of Abhishek = 7×57\times{5}

Weight of Abhishek = 35 kg

The total weight after the increment is 104.

So, the weight of Ayush after the increment is 104 - 35 = 69

Therefore, the weight of Ayush after the increment is 69 kg.


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ഒരു ക്ലാസ്സിലെ ആൺകുട്ടികളുടെയും പെൺകുട്ടികളുടെയും എണ്ണം 1 : 3 എന്ന അംശബന്ധത്തി ലാണ്. 8 പെൺകുട്ടികൾ മാത്രം വരാതിരുന്ന ദിവസം, ആൺകുട്ടികളുടെ എണ്ണത്തിന്റെ ഇരട്ടി പെൺകുട്ടികൾ ഉണ്ടായിരുന്നു. എങ്കിൽ ക്ലാസ്സിലെ ആകെ കുട്ടികളുടെ എണ്ണം എത്ര?
ഒരു ക്ലാസിൽ ആൺകുട്ടികളും പെൺകുട്ടികളും തമ്മിലുള്ള അംശ ബന്ധം 5 : 4 ആണ്. ആ ക്ലാസിൽ 20 പെൺകുട്ടികൾ ഉണ്ടെങ്കിൽ ആൺകുട്ടികളുടെ എണ്ണമെത്ര ?