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This question is based on the five, three-digit numbers given below: (Left) 158 438 182 325 230 (Right) If 5 is added to the first digit of every number, in how many numbers will the first digit be exactly divisible by the second digit?

A2

B4

C3

D1

Answer:

A. 2

Read Explanation:

When 5 is added to the first digit of each number, the new numbers change as follows:

  • 158 becomes 658: The first digit (6) is not exactly divisible by the second digit (5).

  • 438 becomes 938: The first digit (9) is exactly divisible by the second digit (3) because 9÷3=39 \div 3 = 3.

  • 182 becomes 682: The first digit (6) is not exactly divisible by the second digit (8).

  • 325 becomes 825: The first digit (8) is exactly divisible by the second digit (2) because 8÷2=48 \div 2 = 4.

  • 230 becomes 730: The first digit (7) is not exactly divisible by the second digit (3).

There are 2 numbers (438 and 325) that satisfy the condition.


Related Questions:

What will come in the place of the question mark (?) in the following equation if ‘×’ and '÷’ are interchanged and ‘9’ and ‘3’ are interchanged? 2 – 6 ÷ 9 × 3 + 5 =?
- എന്നാൽ ÷ എന്നും, + എന്നാൽ × എന്നും, ÷ എന്നാൽ - എന്നും , × എന്നാൽ '+' എന്നുമായാൽ താഴെ തന്നിട്ടുള്ളവയിൽ ശരിയായ പ്രസ്താവന ഏത്?
÷ = +, + = ×, × = -, - = ÷ ആയാൽ 60 ÷ 7 + 6 × 10 - 5 എത്ര?
x എന്നത് + ഉം ÷ എന്നത് - ഉം - എന്നത് x ഉം + എന്നത് ÷ഉം ആയാൽ 13 x 5 - 20 + 10 ÷ 9 എന്നതിന്റെ വിലയെന്ത് ?
If '+' means '-', '-' means '×', '×' means '÷', and '-' means '+', what will come in place of the question mark (?) in the following equation? 16 + 4 - 8 + 3 × 3 = ?