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Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm respectively are melted and formed into a single cube. The edge of the new cube formed is

A12 cm

B14 cm

C16 cm

D18 cm

Answer:

A. 12 cm

Read Explanation:

Solution:

As we know,

Volume of cube = a3

Three cubes of iron whose edges are 6 cm, 8 cm and 10 cm.

Let the edge of bigger cube be A

Volume of cube of bigger cube = Sum of volume of all three cubes

A3 = 63 + 83 + 103 = 216 + 512 + 1000 = 1728

⇒ A = ∛1728

⇒ A = 12

∴ Edge of bigger cube = 12 cm


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If the length and breadth of a rectangle are in the ratio 3 : 2 and its perimeter is 20 cm, then the area of the rectangle (in sq.cm) is :