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Three of the following four letter-cluster pairs are alike in a certain way and thus form a group. Which is the letter-cluster pair that does NOT belong to that group? (Note: The odd one out is not based on the number of consonants/vowels or their positions in the letter-cluster.)

AAM - KV

BOA - YJ

CKW - UF

DFK - TA

Answer:

D. FK - TA

Read Explanation:

The Correct Pattern:

In three of the pairs, the first letter shifts by +10 positions, and the second letter shifts by +9 positions:

  • AM → KV:

    • A (1) + 10 = K (11)

    • M (13) + 9 = V (22)

  • OA → YJ:

    • O (15) + 10 = Y (25)

    • A (1) + 9 = J (10)

  • KW → UF:

    • K (11) + 10 = U (21)

    • W (23) + 9 = 32 → wraps around to F (6)

The Odd One Out:

  • FK → TA:

    • F (6) + 14 = T (20) (Should be +10 to get P)

    • K (11) + 16 = 27 → wraps around to A (1) (Should be +9 to get T)

Since FK - TA does not follow the (+10, +9) shift pattern, it is the clear odd one out.


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