Question

Three partners A, B, and C divide Rs. 2,21,000 amongst themselves in such a way that if Rs. 2,000, Rs. 3,000, and Rs. 4,000 are removed from the sums that A, B, and C received, respectively, then the share of the sums that they will get are in the ratio 11:18:24. How much (in Rs.) did B receive?

• A. 69,000
• B. 72,000
• C. 96,000
• D. 75,000

Answer 1

Answer:

D. 75,000

Solution: Given: An amount of Rs. 2,21,000 among three partners A, B and C The amount removed from A, B, and C is Rs. 2,000, Rs. 3,000, and Rs. 4,000 respectively. The ratio of divided sums is 11:18:24 Calculations: Let the amount received by A be 11x Let the amount received by B be 18x Let the amount received by C be 24x The total removed amount from A, B, and C is ⇒ 2000 + 3000 + 4000 = 9000 The total amount received by A, B, and C is ⇒ 221000 – 9000 = 212000 The total ratio of the amount is ⇒ 11x + 18x + 24x = 53x According to the question, we have ⇒ 53x = 212000 ⇒ x = 212000/53 ⇒ x = 4000 Amount received by B is 18x = 18 × 4000 = 72000 The total amount received by B is 72000 + 3000 = 75000 ∴ The total amount received by B is Rs. 75,000 Alternate Method The total amount received by A is 11x + 2000 The total amount received by B is 18x + 3000 The total amount received by C is 24x + 4000 According to the question, we have ⇒ A + B + C = 221000 ⇒ (11x + 2000) + (18x + 3000) + (24x + 4000) = 221000 ⇒ 53x + 9000 = 221000 ⇒ 53x = 212000 ⇒ x = 4000 The total amount received by B is 18x + 3000 ⇒ 18 × 4000 + 3000 ⇒ 75000 ∴ The total amount received by B is Rs. 75,000