Two circles have radii of 12 cm and 4 cm. If the length of a direct common tangent is 15 cm, what is the distance between their centers?A15 cmB17 cmC18 cmD20 cmAnswer: B. 17 cm Read Explanation: The formal formula for the length of a direct common tangent (ddd) between two circles is:d=D2−(R−r)2d = \sqrt{D^2 - (R - r)^2}d=D2−(R−r)2Where:ddd = Length of the direct common tangent = 15 cmDDD = Distance between the centers = ?RRR = Radius of the larger circle = 12 cmrrr = Radius of the smaller circle = 4 cmStep 1: Substitute the given values into the formula15=D2−(12−4)215 = \sqrt{D^2 - (12 - 4)^2}15=D2−(12−4)2Step 2: Simplify the radius difference15=D2−(8)215 = \sqrt{D^2 - (8)^2}15=D2−(8)215=D2−6415 = \sqrt{D^2 - 64}15=D2−64Step 3: Square both sides to remove the square root152=D2−6415^2 = D^2 - 64152=D2−64225=D2−64225 = D^2 - 64225=D2−64Step 4: Isolate D2D^2D2D2=225+64D^2 = 225 + 64D2=225+64 D2=289D^2 = 289D2=289Step 5: Take the square root to solve for DDDD=289D = \sqrt{289}D=289 D=17 cmD = \mathbf{17\text{ cm}}D=17 cmThe distance between their centers is 17 cm. Read more in App