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Two circles have radii of 12 cm and 4 cm. If the length of a direct common tangent is 15 cm, what is the distance between their centers?

A15 cm

B17 cm

C18 cm

D20 cm

Answer:

B. 17 cm

Read Explanation:

The formal formula for the length of a direct common tangent (dd) between two circles is:

d=D2−(R−r)2d = \sqrt{D^2 - (R - r)^2}

Where:

  • dd = Length of the direct common tangent = 15 cm

  • DD = Distance between the centers = ?

  • RR = Radius of the larger circle = 12 cm

  • rr = Radius of the smaller circle = 4 cm


  • Step 1: Substitute the given values into the formula
    15=D2−(12−4)215 = \sqrt{D^2 - (12 - 4)^2}

  • Step 2: Simplify the radius difference
    15=D2−(8)215 = \sqrt{D^2 - (8)^2}
    15=D2−6415 = \sqrt{D^2 - 64}

  • Step 3: Square both sides to remove the square root
    152=D2−6415^2 = D^2 - 64
    225=D2−64225 = D^2 - 64

  • Step 4: Isolate D2D^2
    D2=225+64D^2 = 225 + 64
    D2=289D^2 = 289

  • Step 5: Take the square root to solve for DD
    D=289D = \sqrt{289}
    D=17 cmD = \mathbf{17\text{ cm}}

The distance between their centers is 17 cm.


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