Question

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

• A. 39, 30
• B. 41, 32
• C. 42, 33
• D. 43, 34

Answer 1

Answer:

C. 42, 33

Let their marks be (x + 9) and x. x + 9 = 56/100(x + 9 + x) 25(x + 9) = 14(2x + 9) 3x = 99 x = 33 So, their marks are 42 and 33.