Question

Two students appeared for an examination. One of them secured 16 marks more than the other and his marks were 75% of the sum of their marks. The marks obtained by them are:

• A. 98 and 82
• B. 49 and 33
• C. 36 and 16
• D. 24 and 8

Answer 1

Answer:

D. 24 and 8

Let, the marks of first student's be 'x' Then marks of second student's be (x + 16) (x + 16) = 75/100(x + x + 16) x + 16 = 3/4 (2x + 16) 4x + 64 = 6x + 48 2x = 16 ⇒ x = 8 Other student's marks = 8 + 16 = 24