Two trains running in opposite directions cross a man standing on the platform in 27 sec, 17 sec, respectively and they cross each other in 23 sec. The ratio of their speed is:
A3:2
B1:3
C3:4
D4:3
Answer:
A. 3:2
Read Explanation:
Let the speeds of two trains are x m/sec and y m/sec respectively.
Then length of first train = 27 xm
Length of second train = 17 ym
(27x+17y)/(x+y) = 23 27x +17y = 23x+23y 4x = 6y 2x = 3y = x:y = 3:2