Two trains running in opposite directions cross a man standing on the platform in 27 sec, 17 sec, respectively and they cross each other in 23 sec. The ratio of their speed is:

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Two trains running in opposite directions cross a man standing on the platform in 27 sec, 17 sec, respectively and they cross each other in 23 sec. The ratio of their speed is:

A3:2

B1:3

C3:4

D4:3

Answer:

A. 3:2

Read Explanation:

Let the speeds of two trains are x m/sec and y m/sec respectively. Then length of first train = 27 xm Length of second train = 17 ym (27x+17y)/(x+y) = 23 27x +17y = 23x+23y 4x = 6y 2x = 3y = x:y = 3:2

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